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TNPSC Aptitude and Mental Ability Model Question-1 Details:

No. of Questions : 25

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[/vc_column_text][vc_column_text]**Directions: Q. No. 1 to 5: Study the following information carefully to answer these questions. **

Six persons A, B, C, D, E and F are sitting in two rows, three in each. E is not at the end of any row. D is second to the left of F. C, the neighbor of E, is sitting diagonally opposite to D. B is the neighbor of F.

**1.** Which of the following are sitting diagonally opposite to each other?

a. F and C

b. D and A

c. A and C

d. A and F

**d. A and F**

**2.** Which of the following are in the same row?

a. A and E

b. E and D

c. C and B

d. A and B

**a. A and E**

**3.** Which of the following are in one of the two rows?

a. FBC

b. CEB

c. DBF

d. AEF

**C. DBF**

**4.** After Interchanging seat with E, who will be the neighbors of D in the new position?

a. C and A

b. F and B

c. Only B

d. Only A

**a. C and A**

**5. **Which of the following occupies the middle positions in both the rows?

a. B and F

b. A and C

c. B and E

d. E and C

** c. B and E**

**6.** A train moves at a constant speed of 120 km/hr for 1 km and at 40 km/hr for the next 1 km. What is the average speed of the train.

a. 48 kmph

b. 50 kmph

c. 80 kmph

d. 60 kmph

** d. 60 kmph**

Distance = 1 km ,

Speed x = 120 km/hr

Speed y = 40 km/hr

**Average Speed = (2 * x * y) / (x + y) [ie Same Distance]**

** Average Speed = Total Distance / Total Time [ie Different Distance]**

Here the distance is same. So,

Average Speed = (2 * x * y) / (x + y)

= (2 * 120 * 40) / 160

= 60 km / hr

** Answer => 60 km / hr**

**7. **A can do a piece of work in 20 days and B can do it in 15 days and c can finish it in 25 days, then how long will they take to complete the work?

a) 6(18/47) days

b) 12 days

c) 2(8/11) days

d) 47(6/18) days

** a. 6(18/47) days**

A’s 1 day work = 1 / 20

B’s 1 day work = 1 / 15

C’s 1 day work = 1 / 25

(A + B + c)’s 1 day work = (1 / A) + (1 / B) + (1 / C)

(A + B + c)’s 1 day work = (1 / 20) + (1 / 15) + (1 / 25)

LCM of 20, 15, 25 = 300

= (15 + 20 + 12) / 300

= 47 / 300

A, B, C together to complete the work in,

= 300 / 47

= 6 (18 / 47) days

** Answer => 6 (18 / 47) days**

**8. ** Nishu and Archana can do a piece of work in 10 days and Nishu alone can do it in 12 days. In how many days can Archana do it alone?

a) 60 days

b) 30 days

c) 50 days

d) 45 days

**a. 60 days**

(Nishu + Archana)’s 1 day work

** (1 / A) + (1 / B) = (1 / 10)**

Nishu’s 1 day work, (1 / A) = (1/ 12)

Archana’s 1 day work, (1 / B) = ?

( 1/ B) = (1 / 10) – (1/ 12)

LCM of 10, 12 = 120,

= (12 – 10) / 120

= 2 / 120

= 60 days

**Archana alone can finish the work in => 60 days**

**9. **A and B undertake to do a piece of work for Rs.100. A can do it in 5 days and B can do it in 10 days. With the help of C, they finish it in 2 days. How much should C be paid for his contribution?

a) Rs.40

b) Rs. 20

c) Rs. 60

d) Rs. 30

**a. Rs.40**

A’s 1 day work = 1 / 5

B’s 1 day work = 1 / 10

A + B + C’s 1 day work = 1 / 2

To find C’s 1 day work,

(1 / A) + (1 / B) + (1 / C) = 1/ 2

(1 / C) = (1 / 2) – [(1 / A) + (1 / B)]

= (1 / 2) – [(1 / 5) + (1 / 10)]

LCM of 2, 5, 10 = 10

= (5 – 2 – 1) / 10

= (2 / 10)

C’s 1 day work => (1 / 5)

To find the ratio of their 1 day’s work,

** A : B : C = (1 / 5) : (1 / 10) : (1 / 5)**

LCM of 5, 10, 5 is 10

So, A : B : C = 2 : 1 : 2

Here total part is 5.

Total share = 100

C’s share = (2 / 5) * 100

= 40

** C’s share => 40**

**10.** In the following figures two six fold cubes are given. Each side of the cube is painted as shown in these figures. These sides are White, Yellow, Orange, Red, Blue. Studying the arrangement of colours tell when Blue colour is on top which colour will the bottom have?

(a) Red

(b) Green

(c) Orange

(d) Yellow

**d. Yellow**

**11. **Given below are three different positions of a dice. Find the number of dots on the face opposite the face bearing 3 dots.

(a) 4

(b) 5

(c) 6

(d) Cannot be determined

**c. 6**

**12. **What is the unit digit in the product

(3^{65} x 6^{59} x 7^{71})?

a. 1

b. 2

c. 4

d. 6

**c. 4**

**Unit digits of 3 :**

3^{0} = 1, 3^{1} = 3, 3^{2} = 9, 3^{3} = 7, 3^{4} = 1, 3^{5} = 3, 3^{6} = 9, 3^{7} = 7…………

To find the unit digit of 3^{65},

(65 / 4) => Remainder = 1

3^{1} = 3,

So, unit digit of 3^{65 }value is = 3

**Unit digits of 6 :**

6^{0} = 1, 6^{1} = 6, 6^{2} = 6, …….

6 ^{Any number} = 6 (other than 6^{0})

Here, unit digit of 6^{59} = 6

**Unit digits of 7 :**

7^{0} = 1, 7^{1} = 7, 7^{2} = 9, 7^{3} = 3, 7^{4} = 1, 7^{5} = 7, 7^{6} = 9, 7^{7}=3,……….

To find the unit digit of 7^{71},

71 / 4 => Remainder 3

7 / 3 = 3

So, unit digit of 7^{71} = 3

Unit digit in the product of 3^{65} * 6^{59} * 7^{71},

= 3 * 6 * 3

= 4

**Unit digit in the product of 3 ^{65} * 6^{59} * 7^{71 }=> 4**

**13. **If the number 653xyis divisible by 90, then (x + y) = ?

a. 2

b. 3

c. 4

d. 6

**C. 4**

If a number is divisible by 3, 9, 10 means, it is divisible by 90.

If a number is divisible by 9, it can be divisible by 3 also.

So, only check if a number is divisible by 9 and 10.

Here, 653 * y ÷ 90,

From the option,

x + y = 4,

6 + 5 + 3 + 4 = 18 (divisible by 9)

x = 4

y = 0

65340 ÷ 90

**So, x + y = 4**

**14. **If the number 517*324 is completely divisible by 3, then the smallest whole number in the place of * will be:

a. 0

b. 1

c. 2

d. None of these

**C. 2**

If the sum of the digits of a number is divisible by 3. Then the number is divisible by 3.

Here,

517*324 is divisible by 3,

So,

5 + 1 + 7 + 3 + 2 + 4 = 22

The smallest whole number in the place of * is = 2.

22 + 2 = 24 divisible by 3.

** Answer => 2**

**Directions (Q.No. 15 – 17):** The six winners – K, L, M, N, O and P – of a national science contest each won a college scholarship. The prizes for first through sixth place were $30,000, $25,000, $20,000, $15,000, $10,000, and $5,000. The following information concerning the winners was released:

O won the $20,000 prize.

K won less money than L did.

The difference between the winnings of M and P was $5,000.

The difference between the winnings of N and P was at least $10,000

**15. **Which of the following could be the ranking, from sixth place through first place, of the six students?

a. M, P, L, O, N, K

b. N, P, M, O, K, L

c. N, M, K, O, L, P

d. M, P, K, O, N, L

** d. M, P, K, O, N, L**

**16. **If K won $10,000, how much money in total did M and P win?

a. $15,000

b. $25,000

c. $35,000

d. $55,000

**d. $55,000**

**17. **If L won $25,000, which of the following must be true?

a. N won $30,000

b. K won $15,000

c. P won $15,000

d. M won $5,000

**a. N won $30,000**

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**18. **A and B are married couple. X and Y are brothers. X is the brother of A. How is Y related to B?

a) Brother-in-Law

b) Brother

c) Son-in-law

d) Cousin

**a. Brother-in-law**

**19.** If

(i) M is brother of N;

(ii) B is brother of N; and

(iii) M is brother of D,

then which of the following statements is definitely true?

a. N is brother of B

b. N is brother of D

c. M is brother of B

d. D is brother of M

**c. M is brother of B**

**20.** What will come in the place of a question mark?

**b. 9**

**21. ** What number should come in the place of question mark?

(a) 18 (b) 33 (c) 135 (d) 145

**c.135**

**Directions for the following 4 (Four) items:**

Examine carefully the following statements and answer four items that follow:

(i) A and B play Football and Hockey

(ii) C and D play Badminton and Cricket

(iii) B and C play Cricket and Football

(iv) A and D play Hockey and Badminton

**22.** One who plays Badminton, Football and Hockey

(a) A (b) B

(c) C (d) D

**a. A**

**23.** One who plays Badminton, Football and Cricket

(a) A (b) B

(c) C (d)D

**c. C**

**24.** One who plays Cricket, Football and Hockey

(a) A (b) B

(c) C (d) D

**b. B**

**25.** One who does not play cricket

(a) A (b)B

(c) C (d)D

**a. A **

TNPSC Aptitude and Mental Ability Questions with solutions for practice. Practice these tnpsc aptitude and reasoning model questions for tnpsc Group 1, Group 2, Group 2A, Group 3, Group 4, VAO and other exams.[/vc_column_text][/vc_column][/vc_row]

hello sir.. i think ”8th question in aptitude and mental ability with answers1” related to lcm is wrong..

8. Nishu and Archana can do a piece of work in 10 days and Nishu alone can do it in 12 days. In how many days can Archana do it alone?

lcm will be 60 and answer will be 10 days i think. please check and reply sir…

Thank you….

Hi,

The answer of Question 8 is Correct. Its not wrong. Can you explain how you solved this sum, We will explain you whether you can do in that way.

Oopsss… Sorry sir.. wrongly posted.. 8th questions answer is right.. It was my mistake.. sorry and thank you… !!!

Oh, Its Ok. Welcome.

Greetings to your team,

Your test series are very useful to me. Please upload a aptitude videos in topic wise, it is easy to understand. Please upload soon

Hi,

We are preparing all TNPSC Apps, will update soon.

Hi,

Could you please mention how the 20th question was solved?

Nice

HI THIS IS THARUN , I ORDERED APTITUDE BOOK FROM TNPSC ACADEMY, I HAVE A DOUBT IS THE BOOK IN SOLVED MANNER