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Test Question With Solution – Percentage
[/vc_column_text][vc_column_text]1.50 kg is what percent of 250 kg?
a) 26% b) 15% c)20% d) 18%[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%23113af4″ custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1491036277627-2f0fc1f4-0e1e” use_custom_heading=”true”]Here Percentage is asked, so, Formula 1
(50/250) x 100
= 20%
Answer ==> C) 20%[/vc_toggle][vc_column_text]2.If 20% of x= 90, find x.
a) 350 b) 450 c) 250 d) 550[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%233804f2″ custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1491036605984-c85ac97e-0bf6″ use_custom_heading=”true”]Here percentage is given,
20% of x = 90
x X (20/100) = 90
x = (90 x 100)/20
x = 450
Answer ==> b) 450 [/vc_toggle][vc_column_text]3. What is 5% of 50% of 500?
a) 12.5 b) 25 c) 1.25 d)6.25[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%230602f2″ custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1491037121201-6312614a-8a91″ use_custom_heading=”true”]5 % of 50 % of 500
Let us take : 50 % of 500
then [500 x(50/100)]
Now, 5% of [500 x(50/100)]
Therefore, [500 x (50/100)] x (5/100) = 25/2
=12.5
Answer ==> a) 12.5[/vc_toggle][vc_column_text]4. A person’s salary has increased from Rs. 7200 to 8100. what is the percentage increase in salary?
a) 25 % b)18 % c)16 2/3 % d)12 1/2 %[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%230d09ef” custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1491037517145-7c0b1700-068b” use_custom_heading=”true”]
% change = (change in value / initial value) x 100
change in value = 8100 – 7200
= 900
% change = (900/7200) x 100
=12.5
Answer ==> d) 12 1/2[/vc_toggle][vc_column_text]5. The strength of a college was 3000 last year. If there is an increase of 20 % this year the the present strength is
a) 3200 b) 3400 c) 3600 d) 3800[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%230300e8″ custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1491040160481-60d91a4d-de60″ use_custom_heading=”true”]
Strength = 3000
increment = 3000 x (20/100)
= 600
present strength = 3000 + 600
= 3600
Answer ==> c) 3600[/vc_toggle][vc_column_text]6. In a company, there are 724 employees. 25 % employees left the job. Find the number of rest of employees.
a) 543 b) 550 c) 578 d) 565[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%233004f2″ custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1491040443956-a13fc553-6920″ use_custom_heading=”true”]
Total employees = 724
25 % of 724 = 724 x (25/100)
= 181
181 employees left the company.
therefore, 724 – 181 = 543
Answer ==> a) 543[/vc_toggle][vc_column_text]7. The population of a town is 126800 increases by 15% in the first year and decreases by 20 % in the second year. What is the population of the town at the end of second year?
a) 174984 b) 135996 c) 116656 d) 145820[/vc_column_text][vc_column_text]8) The length of a rectangle is increased by 50%. By what percent would the breadth have to be decreased to maintain the same area?
a) 37.5 % b) 33.33 % c) 25 % d) None of these.[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%234d0cf2″ custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1491284102390-1a138778-b6bf” use_custom_heading=”true”]
area of rectangle = L x B
let initial L = 100% B = 100%
So, area = 100 x 100 = 10000
length is increased by 50 %, New length = 150
area = 150 x b = 10000 (same area)
b = 10000/150
b = 66.66 %
Question is By what % breadth have to be decreased?
So, % change = (change in value)/(Initial Value x 100)
= [(100 – 66.66%)/100] x 100
= 33.33 %
Answer = b) 33.33 %[/vc_toggle][vc_column_text]9) Find the percentage increase in the area of a triangle if its each side is doubled.
a) 100 % b) 200 % c) 300 % d) 400 %[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%234d0cf2″ custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1495121873962-e73a0090-2a24″ use_custom_heading=”true”]
area = 1/2 bh
If sides are doubled, then b = 2b; h = 2h
Then, area = 1/2 (2b x 2h)
= 2bh
% difference = ((Final value – Initial Value)/Initial Value ) X 100
= ((2bh – 0.5 bh) / 0.5 bh) X 100
= 1.5 x 2 x 100
= 300 %
[/vc_toggle][vc_column_text]10) Ramesh spent 20% of his pocket money on buying clothes. After spending 25% of the remainder in buying shoes, he has Rs.480 left. What was his pocket money?
a) Rs.600 b) Rs.800 c) Rs.900 d) Rs.1000[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%234d0cf2″ custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1495122153569-59eb8c7f-24b6″ use_custom_heading=”true”]
Let the total pocket money be Y.
Rupees spent on clothes is Y * 20/100
The remaining amount after spending on clothes is,
Y – (20Y/100) ; [ Y -> Total ; (20Y/100) -> Clothes ]
= (100Y – 20Y)/100
= 80Y/100
25 % of the above remainder is spent on shoes, therefore
25 % of (80Y/100) = (25/100) * (80Y/100)
= (80Y * 25) / 10000
= 2000 Y / 10000
Therefore, Total Money Y = (20Y/100) + (2000Y/10000) + 480
(clothes) + (shoes) + (remaining left)
Y = (2000Y + 2000 Y + 4800000 ) / 10000
Y = (4000 Y + 4800000 ) / 10000
10000 Y = 4000 Y + 4800000
10000 Y – 4000 Y = 4800000
6000 Y = 4800000
Y = 4800000 / 6000
Y = 800 rupees
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Watch TNPSC Aptitude video class in Tamil & English – Percentage
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9th n 10th question solutions plz
Will update soon.
9th and 10th solutions updated.
Thank u 🙂
You are welcome.
pls upload the video of profit and loss aptitude sir
is tr any shrt ct for 10th qtn
really it is useful to me and very easy to understand thank a lot sir
You are welcome.
I did understand one problem from your practice type question while checking the answer in the time.
Ramesh spent 20% of pocket mny on buy clothes. After spending 25% if remainder shoes, he has rs. 480 left. What was his pocket money.
1. 25% he spend for shoes.
let 100%= 25% + 480 ie( 480=75%)
so 25%= 480/3= 160
then 100%= 160+480 = 640
2. 20% he spend for cloths
let 100%= 20%+ 640(640= 80%)
so 20%= 160 (i.e 640/4)
so finally the 100% = 160+640=800
hope u got it ????
Very easy to understand.
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