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Test Question With Solution – Percentage
[/vc_column_text][vc_column_text]1.50 kg is what percent of 250 kg?
a) 26% b) 15% c)20% d) 18%[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%23113af4″ custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1491036277627-2f0fc1f4-0e1e” use_custom_heading=”true”]Here Percentage is asked, so, Formula 1
(50/250) x 100
= 20%
Answer ==> C) 20%[/vc_toggle][vc_column_text]2.If 20% of x= 90, find x.
a) 350 b) 450 c) 250 d) 550[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%233804f2″ custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1491036605984-c85ac97e-0bf6″ use_custom_heading=”true”]Here percentage is given,
20% of x = 90
x X (20/100) = 90
x = (90 x 100)/20
x = 450
Answer ==> b) 450 [/vc_toggle][vc_column_text]3. What is 5% of 50% of 500?
a) 12.5 b) 25 c) 1.25 d)6.25[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%230602f2″ custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1491037121201-6312614a-8a91″ use_custom_heading=”true”]5 % of 50 % of 500
Let us take : 50 % of 500
then [500 x(50/100)]
Now, 5% of [500 x(50/100)]
Therefore, [500 x (50/100)] x (5/100) = 25/2
=12.5
Answer ==> a) 12.5[/vc_toggle][vc_column_text]4. A person’s salary has increased from Rs. 7200 to 8100. what is the percentage increase in salary?
a) 25 % b)18 % c)16 2/3 % d)12 1/2 %[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%230d09ef” custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1491037517145-7c0b1700-068b” use_custom_heading=”true”]
% change = (change in value / initial value) x 100
change in value = 8100 – 7200
= 900
% change = (900/7200) x 100
=12.5
Answer ==> d) 12 1/2[/vc_toggle][vc_column_text]5. The strength of a college was 3000 last year. If there is an increase of 20 % this year the the present strength is
a) 3200 b) 3400 c) 3600 d) 3800[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%230300e8″ custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1491040160481-60d91a4d-de60″ use_custom_heading=”true”]
Strength = 3000
increment = 3000 x (20/100)
= 600
present strength = 3000 + 600
= 3600
Answer ==> c) 3600[/vc_toggle][vc_column_text]6. In a company, there are 724 employees. 25 % employees left the job. Find the number of rest of employees.
a) 543 b) 550 c) 578 d) 565[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%233004f2″ custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1491040443956-a13fc553-6920″ use_custom_heading=”true”]
Total employees = 724
25 % of 724 = 724 x (25/100)
= 181
181 employees left the company.
therefore, 724 – 181 = 543
Answer ==> a) 543[/vc_toggle][vc_column_text]7. The population of a town is 126800 increases by 15% in the first year and decreases by 20 % in the second year. What is the population of the town at the end of second year?
a) 174984 b) 135996 c) 116656 d) 145820[/vc_column_text][vc_column_text]8) The length of a rectangle is increased by 50%. By what percent would the breadth have to be decreased to maintain the same area?
a) 37.5 % b) 33.33 % c) 25 % d) None of these.[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%234d0cf2″ custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1491284102390-1a138778-b6bf” use_custom_heading=”true”]
area of rectangle = L x B
let initial L = 100% B = 100%
So, area = 100 x 100 = 10000
length is increased by 50 %, New length = 150
area = 150 x b = 10000 (same area)
b = 10000/150
b = 66.66 %
Question is By what % breadth have to be decreased?
So, % change = (change in value)/(Initial Value x 100)
= [(100 – 66.66%)/100] x 100
= 33.33 %
Answer = b) 33.33 %[/vc_toggle][vc_column_text]9) Find the percentage increase in the area of a triangle if its each side is doubled.
a) 100 % b) 200 % c) 300 % d) 400 %[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%234d0cf2″ custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1495121873962-e73a0090-2a24″ use_custom_heading=”true”]
area = 1/2 bh
If sides are doubled, then b = 2b; h = 2h
Then, area = 1/2 (2b x 2h)
= 2bh
% difference = ((Final value – Initial Value)/Initial Value ) X 100
= ((2bh – 0.5 bh) / 0.5 bh) X 100
= 1.5 x 2 x 100
= 300 %
[/vc_toggle][vc_column_text]10) Ramesh spent 20% of his pocket money on buying clothes. After spending 25% of the remainder in buying shoes, he has Rs.480 left. What was his pocket money?
a) Rs.600 b) Rs.800 c) Rs.900 d) Rs.1000[/vc_column_text][vc_toggle title=”Solution” custom_font_container=”tag:h2|font_size:17|text_align:left|color:%234d0cf2″ custom_google_fonts=”font_family:Vollkorn%3Aregular%2Citalic%2C700%2C700italic|font_style:400%20regular%3A400%3Anormal” el_id=”1495122153569-59eb8c7f-24b6″ use_custom_heading=”true”]
Let the total pocket money be Y.
Rupees spent on clothes is Y * 20/100
The remaining amount after spending on clothes is,
Y – (20Y/100) ; [ Y -> Total ; (20Y/100) -> Clothes ]
= (100Y – 20Y)/100
= 80Y/100
25 % of the above remainder is spent on shoes, therefore
25 % of (80Y/100) = (25/100) * (80Y/100)
= (80Y * 25) / 10000
= 2000 Y / 10000
Therefore, Total Money Y = (20Y/100) + (2000Y/10000) + 480
(clothes) + (shoes) + (remaining left)
Y = (2000Y + 2000 Y + 4800000 ) / 10000
Y = (4000 Y + 4800000 ) / 10000
10000 Y = 4000 Y + 4800000
10000 Y – 4000 Y = 4800000
6000 Y = 4800000
Y = 4800000 / 6000
Y = 800 rupees
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Watch TNPSC Aptitude video class in Tamil & English – Percentage
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